tim x , biet :
a) x + \(\dfrac{3}{10}\)= \(\dfrac{-2}{5}\)
b) x + \(\dfrac{5}{6}\) = \(\dfrac{2}{5}\) - \(\left(-\dfrac{2}{3}\right)\)
c) \(1\dfrac{2}{5}\) x + \(\dfrac{3}{7}\) = \(-\dfrac{4}{5}\)
d) \(\left[x+\dfrac{3}{4}\right]-\dfrac{1}{3}=0\)
e) \(\left[x+\dfrac{4}{15}\right]-\left[-3,75\right]=-\left[-2,15\right]\)
f) \(\left(x-2\right)^2=1\)
g) \(\left(2x-1\right)^3=-27\)
h) \(\dfrac{x-1}{-15}=\dfrac{-60}{x-1}\)
i) x : \(\left(\dfrac{-1}{2}\right)^3=\dfrac{-1}{2}\)
j) \(\left(\dfrac{3}{4}\right)^5.x=\left(\dfrac{3}{4}\right)^7\)
k) \(8^x:2^x=4\)